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lara [203]
3 years ago
5

Help of using proportion to solve problems

Mathematics
1 answer:
Sindrei [870]3 years ago
4 0

Hint: it will help to change all denominators to the same one using gcf or lcm
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What is the first quartile of this data set?
Mamont248 [21]
The median is 19 and the lower quartile is the middle number of the 5 numbers before 19 
So its 13 

B
5 0
2 years ago
Read 2 more answers
If there are 80 toys in a shop, 40% of them are for boys. 50% of the boy's toys and 50% of the girl's toys are made by the shop
lana [24]

Answer: 8 more girl toys than boy toys

Step-by-step explanation:

First you need to find out how many of the toys are for boys and girls.

———————————————

80 * 40 = 80 * 0.4 = 32

32 toys are for boys

———————————————

80 - 32 = 48

48 toys are for girls

———————————————

Now find 50% of the boy and girl toys.

32 * 50% = 32 * 0.5 = 16

48 * 50% = 48 * 0.5 = 24

———————————————

Now subtract the number of girl toys by the number of boy toys to find out how many more were made for girls than boys.

24 - 16 = 8

3 0
3 years ago
Read 2 more answers
Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

                                               =3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z

Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
A pen stand costs ₹120. How many pen stand can be bought for ₹1440​
siniylev [52]

1440 divided by 120 = 12 pen stands

hope it helps:))

6 0
3 years ago
ITS URGENT PLEASE HELP ME
Iteru [2.4K]
I think that it is D or A
3 0
2 years ago
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