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postnew [5]
3 years ago
8

I’ve retaken this quiz twice and i just need to finish

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0
I believe the answer is A
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Find the value of x in the parallelogram
const2013 [10]

Answer:

x=50

Step-by-step explanation:

we know that

If LM is the midsegment

then

LM=\frac{1}{2}(AB+DC)

substitute the given values

4x+3=\frac{1}{2}(x+8+348)

Solve for x

8x+6=(x+356)

8x-x=356-6

7x=350

x=350/7

x=50

3 0
3 years ago
Please Help I will give out brainliest
gizmo_the_mogwai [7]

Answer:

when y=1 then x=0.5

Step-by-step explanation:

The graph is provided.

The equation y=4x-1 can be graphed by first graphing the -1 which is the y-intercept in the y=mx+b form. 4=m that is our slope. you can find the lines second point by moving 4 up and 1 to the right. rise/run =4/1. So when you move 4 up and 1 right you get another point on the line (1,3).

You can find out x=0.5 when y=1 by just tracing your finger over the graph and the point when y equals 1 the line intercepts x=0.5. Another screenshot is given.

I hope this helps!

8 0
3 years ago
A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th
ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

The information provided is:

N=1500\\n=183\\\sigma=1.47\\\bar x=3.3

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

     =3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0
3 years ago
Last week, Tina worked 40 hours in 4 days. She worked the same number of hours each day. How many hours did she work each day? W
blsea [12.9K]

She works 10 hour per day

3 0
3 years ago
What is the range of this function?
tigry1 [53]
I think it’s B but I dint really know
4 0
3 years ago
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