y= mx+b
(16, -7) = (x,y)
2(16) - 3y = 12
32 - 3y = 12
32 - 12 = 3y
20/3 = y
6.6 = y
2x-3(-7) = 12
2x+21 = 12
2x = 12 - 21
x = -9/2
Insert the values into y = mx + b
solve for m and then solve for b
Answer:
C
Step-by-step explanation:
According to SohCahToa, cosine is adjacent over the hypotenuse.
The adjacent when looking from angle b, is 21.
The hypotenuse of this triangle is 29.
So Cos B=21/29
Answer:
<u><em></em></u>
- <u><em>The length of the image of the segment GH would be 5 units.</em></u>
Explanation:
You can use the <em>center of dilation</em> as your origin of coordintes.
Thus, the <em>point H</em> would have coordinates (0,0) and the <em>point G</em> (-1,0).
A <em>dilation</em> multiplies the coordinates by the <em>scale factor</em>. Hence:
- H = (0,0) → H' = 5 × (0,0) = (0,0)
- G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)
Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.
if it has a diameter of 8, that means its radius is half that, or 4.
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=4\\ h=5 \end{cases}\implies V=\cfrac{\pi (4)^2(5)}{3}\implies V=\cfrac{80\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{using~\pi =3.14}{V= 83.7\overline{3}}~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D4%5C%5C%0Ah%3D5%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%284%29%5E2%285%29%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B80%5Cpi%20%7D%7B3%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BV%3D%2083.7%5Coverline%7B3%7D%7D~%5Chfill%20)
Answer:
128 degrees
Step-by-step explanation:
38+90=128
