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3 years ago

Please HELP!! It’s due today

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

Answer:

For C all she has to do is look at the chart-

0=0

1=4

2=8

3=12

4=16

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$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
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$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
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$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
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$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
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\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
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notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

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