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BaLLatris [955]
3 years ago
7

What is equivalent to 2/5

Mathematics
2 answers:
LuckyWell [14K]3 years ago
7 0
There are many answers. I’ll give you three examples...

4/10
6/15
8/20

There is a pattern too, just a trick!
vlabodo [156]3 years ago
3 0
4/10
6/15
8/20
10/25
12/30
14/35
16/40
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What is 14145 divided by 23?
Kobotan [32]

Answer:

615

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Someone help and make sure the answer is right please and thank you!!!! :)
timama [110]

Answer:

A, 6

Step-by-step explanation:

50=8x+2

<em>subtract</em> 2 from both sides

48=8x

<em>divide</em> both sides by 8

x = 6

<em>plz mark me brainliest</em> ;)

3 0
2 years ago
Please help! While mining, Mike found a large metal bar that contained 6 ounces of lead. Mike also determined that the bar was 4
Dima020 [189]

Answer:

15 ounces

Step-by-step explanation:

6/40 = 0.15

0.15 x 100 = 15

15 ounces

7 0
2 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
Identify the percent of change as an increase or a decrease. 24 songs to 78 songs Increase Decrease Question 2 Find the percent
algol [13]
1)increase
2)225%
Thats the answers
6 0
3 years ago
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