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Mademuasel [1]
3 years ago
14

Five times a number decreased by nine is equal to twice the number increased by 23. Which equation could be used to solve the pr

oblem?
Rachna has nickels, dimes, and quarters in her piggy bank. She has $4.65 altogether. She has three more quarters than dimes and twice as many nickels as quarters. How many quarters does Rachna have?

Three times a number, x, increased by four is equal to five times the number, x. Which equation can be used to solve for x?

What is the value of x in the equation 0.2(x + 1) + 0.5x = –0.3(x – 4)?
Mathematics
2 answers:
Galina-37 [17]3 years ago
6 0

Answer:

Part 1) 5x-9=2x+23

Part 2) 11\ quarters

Part 3) 3x+4=5x

Part 4) x=1

Step-by-step explanation:

Part 1)

Let

x-----> the number

The expression" Five times a number decreased by nine is equal to twice the number increased by 23", is equal to the algebraic expression

5x-9=2x+23

Part 2) we have that

1\ nickel=\$0.05

1\ dime=\$0.10

1\ quarter=\$0.25

Let

x------> the number of nickels

y-------> the number of dimes

z-------> the number of quarters

0.05x+0.10y+0.25z=4.65

Multiply by 100 both sides

5x+10y+25z=465 ------> equation A

z=3+y -----> isolate the variable y

y=z-3 ------> equation B

x=2z ------> equation C

substitute equation B and equation C in equation A

5(2z)+10(z-3)+25z=465

10z+10z-30+25z=465

45z=465+30

45z=495

z=11\ quarters

Part 3) we know that

Let

x------> the number

The equation that represent the expression is equal to

3x+4=5x

Part 4) we have

0.2(x+1)+0.5x=-0.3(x-4)

Multiply by 10 both sides

2(x+1)+5x=-3(x-4)

2x+2+5x=-3x+12

7x+3x=12-2

10x=10

x=1

kotegsom [21]3 years ago
4 0
The first one is 5x-9=2x+23

The third one is 3x+4=5x
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Explanation:

1. Let us first multiple the first equation in System A with 4, we would get:
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Now add the equation (A) and the second equation of System A:

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