39
6^2 + 12 - 3^2
36+12-9
39
Area of the rectangular mat = 12 x 4 = 48 in²
Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²
P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)
Answer: The probability of landing in one of the circles is 0.79.
<span>From the time of my beginning, my part was made of fibrous material called collagen, which is secreted by </span>osteoblasts.
9/6 = 1 3/6
⇒ which equal 1 1/2
