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juin [17]
3 years ago
15

Tell whether the given ordered pair is a solution of the equation 4y + 2x = 3; (1.5,0)

Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0
Plug in the x-value for x and the y-value for y.
4(0) + 2(1.5) =3
3 = 3
The ordered pair is a solution.
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Yin wants to create figure Y′ that is similar to figure Y. Yin begins by reflecting figure Y across the y-axis.
Sholpan [36]

Answer: B) Dilate by scale factor of 2

====================================================

Explanation:

Your teacher isn't saying this directly, but I'm assuming s/he wants you to find a similar figure that isn't congruent to the original. Informally, your teacher seems to want you to find a figure that is the same shape but not the same size as the original.

If so, then any dilation will shrink or enlarge the image depending on the scale factor. So the new image will not be the same as the old one. In this case, a dilation with scale factor 2 means the new figure is twice as large (each side is twice as long). But the old image is similar to the new image. The angles keep their values and therefore we get the same shape. This is why choice B is the answer. Again this is assuming what I mentioned in the first paragraph.

Choices A, C, and D are all known as rigid transformations and they preserve the same size of the figure. Applying any of those operations will lead to the same figure (just rotated, reflected or shifted somehow). In other words, applying operations A,C, or D will have us get two congruent triangles. If two triangles are congruent, then they are automatically similar, but not vice versa. This is why we can rule out A,C, and D.

3 0
3 years ago
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What is the sum of the number of faces, edges, and vertices for a rectangular prism?
Vera_Pavlovna [14]

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4 years ago
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Answer:

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

Step-by-step explanation:

The volume of the swimming pool can be written as;

Volume V = flow rate × time

V = R×t

V = R1×t1 = R2×t2

R1×t1 = R2×t2

t2 = R1×t1/R2 ........1

Given;

Flow rate R1 = 12 litres per minute

Flow rate R2 = 5 litres per minute

time t1 = 22 hours

Substituting the given values into equation 1;

t2 = R1×t1/R2 = 12×22/5

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

3 0
3 years ago
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