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Setler79 [48]
2 years ago
14

Suppose that your school's environmental club wants to travel to the state capital to participate in an Earth Day festival. The

rental of a bus for the day will cost $895. Lunch and festival activities will cost $25 per student. Your club advisor thinks that the fee for participating should not be more than $60. How many students must be recruited for the trip. Write a mathematical model for this.
Mathematics
1 answer:
Assoli18 [71]2 years ago
5 0

Answer:

Mathematical model is:

(895/n) + 25 ≤ 60

Number of students must not be less than 26

Step-by-step explanation:

We are told that;

- the rental of a bus for the day will cost $895.

- Lunch and festival activities will cost $25 per student

If the number of students are n, then cost per student for bus rent is; $895/n

Thus, total amount per n number of students to participate is;

895/n + 25

Now, we are told that the club advisor thinks that the fee for participating should not be more than $60.

Thus in form of inequality, we have;

(895/n) + 25 ≤ 60

Subtract 25 from both sides to get;

(895/n) ≤ 60 - 25

(895/n) ≤ 35

Multiply both sides by n and then divide both sides by 35;

895 ≤ 35n

26 ≤ n

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Please help if you are good at math :( thank you
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Answer:

your answer will be

A)(6,10)

B)(2,12)

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Step-by-step explanation:

hope this helps

have a nice day/night ^_^

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f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}

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