You have learned about special right triangles. Using that knowledge, you decide to take a square cake with 10-inch sides and di
vide it diagonally to form two special right triangles. Find and explain how you know the exact (no decimals) measure of the hypotenuse.
Now find the exact diagonal measure of cakes that are an 8-inch square, a 12-inch square, and a 15-inch square.
Did you discover a shortcut that works with any square cake? Explain.
Please show your work
Now find the exact diagonal measure of cakes that are an 8-inch square, a 12-inch square, and a 15-inch square.
Did you discover a shortcut that works with any square cake? Explain.
Please show your work
1 answer:
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Answer:
- sin = -√3/2
- cos = -1/2
- tan = √3
- sec = -2
- csc = (-2/3)√3
- cot = (√3)/3
Step-by-step explanation:
See the attached picture for a drawing of the angle and its terminal point coordinates. Those are (cos(4π/3), sin(4π/3)), so we have the following trig function values:
sin(4π/3) = -√3/2
cos(4π/3) = -1/2
tan(4π/3) = sin/cos = √3
sec(4π/3) = 1/cos = -2
csc(4π/3) = 1/sin = -(2√3)/3
cot(4π/3) = 1/tan = (√3)/3
_____
<em>Additional comment</em>
It helps to know that 1/√a = (√a)/a. This lets you write the ratios with a rational denominator in each case.
