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spin [16.1K]
4 years ago
14

sketch and label all possible rectangles with a perimeter of 30 cm and sides whose lengths are whole numbers

Mathematics
2 answers:
GalinKa [24]4 years ago
6 0
For example, you can draw a rectangle that has two opposite sides of 8, and the other two sides of 7. So they'll add up to be 8+8+7+7, which equals 30 (because the perimeter is all the lengths of the sides added up).
Ivahew [28]4 years ago
3 0
Its asking you to draw rectangles with sides that equal 30 cm for example 

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Y=x-5; domain = {4,6,8}
Lostsunrise [7]

Answer:

Range = {-1, 1, 3}

Step-by-step explanation:

<u><em>The question asks for the range.</em></u>

The function given is

y=x-5

The domain is the set of 3 numbers:

Domain = {4,6,8}

We need to find the range.

First, the range is the set of all y-values for which the function is defined.

When we will be given the domain with a set of numbers, the range would be the numbers that we get when we evaluate the the function at those numbers.

So, we evaluate the function (y-values) at x = 4,6, and 8.

At x = 4:

y=x-5\\y=4-5\\y=-1

At x = 6:

y=x-5\\y=6-5\\y=1

At x = 8:

y=x-5\\y=8-5\\y=3

Thus, the range is:

Range = {-1, 1, 3}

7 0
3 years ago
Erin makes a paper chain. Each loop of the paper chain is about 3 inches long. Erin puts 8 loops of paper together. About how lo
prohojiy [21]
For eight loop, multiply it by 3 to get the whole length of loop
8 x 3 = 24 inches
Since 12 inches is equivalent to 1 feet, convert that
24 inches * (1 feet / 12 inches) = 2 feet

5 0
3 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
4 years ago
8t=56 plsssssss helppp mee
k0ka [10]
8t = 56
t = 56/8
t = 7
5 0
3 years ago
Read 2 more answers
Consider two bases B = {b1, b2, b3} and C = {c1, c2, c3} for a vector space V such that
Helen [10]
I’m a failure if you can just say “yes you are” in the comments
3 0
3 years ago
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