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lbvjy [14]
3 years ago
13

Can you guys please help me?

Mathematics
2 answers:
Likurg_2 [28]3 years ago
6 0

Answer:

First blank(reading from top to bottom left to right) : 21 second blank: 21 third blank: 5 fourth blank: 4 fifth blank: 5.25 or 5 and 1/4 or 21/4

Step-by-step explanation:

To solve this you will first need to make 4 and 1/5 into a improper fraction. To do that you multiply 4 and 5 and get 20. Then you add the 1, and get 21. That will go in your first blank. Next you will remember your KCF (Keep Change Flip) rule. Keep the 20/5, change the division sign to a multiplication sign, and flip 4/5 to 5/4. Next you will just multiply across. 21*5=105      5*4=20  The Directions say to have your answer in simplest form. 105/20 is not in it's simplest form. To make 105/20 in simplest form you would just divide. Your answer on a calculator makes out to be: 5.25. That is just 5 and 1/4 in fraction form, or 21/4 in improper fraction form.

Alinara [238K]3 years ago
3 0

Answer:

answer below

Step-by-step explanation:

They want you to put the first fraction in mixed numbers.

21/5 divided by 4/5

When dividing fractions flip the second fraction

21/5 times 5/4

Then multiply across

105/20 = 21/4 or 5.25

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\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}&#10;&#10;

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