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Rina8888 [55]
3 years ago
11

Determine the discriminant for the quadratic equation 0=-2x2+3. Based on the discriminant value, how many real number solutions

does the equation have?
Discriminant = b2-4ac


0

1

2

24
Mathematics
2 answers:
fiasKO [112]3 years ago
8 0

Answer:

the answer is D

Step-by-step explanation:

on edge2020

nekit [7.7K]3 years ago
4 0

Answer:

Option D.

The discriminat is equal to 24 which

Step-by-step explanation:

The quadratic equation is

-2x² + 3 = 0

Discriminat in quadratic equation tells us the number of solution a quadratic equation has.

For example, the quadratic equation

Ax² + bx + c = 0 will have a discriminat of b² - 4ac.

b² - 4ac is equal to the value of the discriminat and equal to the number of solutions the quadratic equation has.

In our question, we have -2x² + 3 = 0

A = -2

B = 0

C = 3

b² - 4ac = 0

Substitute the values into the above equation.

0² - 4(-2 ×3) = 0

0 + -4 × -6 = 0

24 = 0

The discriminat of the equation is 24

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Step-by-step explanation:

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Given that ;

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Use synthetic division to answer this.  If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.

We use -7 as the divisor in synth. div.  This comes from the factor (x + 7):

-7   /    1    3     2     -8

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     -------------------------

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Step-by-step explanation:

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