∫( (sinx) / (2 - 3cosx)) dx.
From laws of integration: ∫ f¹(u) / f(u) du = In(f(u)) + constant.
d/dx (2 - 3cosx) = 0 -3(-sinx) = 3sinx.
1/3d/dx(2 - 3cosx) = (1/3)*3sinx = sinx.
∫ ((sinx) / (2 - 3cosx)) dx. = ∫ ((1/3) d/dx (2 - 3cosx) / (2 - 3cosx))dx
= 1/3 ∫ (d/dx (2 - 3cosx) / (2 - 3cosx))dx
= (1/3)ln(2 - 3cosx) + Constant.
(let x represent the blank)
3/8 + 2/3 = x + 3/8
25/24 = x + 3/8
subtract 3/8 from both sides of the equation
2/3 = x
Answer:
10
Step-by-step explanation:
Means back the numbers into multiples of several small numbers
Like:; 1. We take LCM of 40
Just break into multiples of small number
40= 2×2×2×5
2. We take LCM of 50
50= 5×5×2
So LCM for 100 is 2×2×5×5
after that see the pairs in the LCM like 2×2 or 3×3 or 4×4(same numbers)
Then write the the single number in place of two multipled numbers
Like:; 2×2 is written as 2 // 3×3 is written as 3
So we can write 100 into 2×2×5×5 and then after selecting pairs (2×2)×(5×5)
write pairs in single number 2×5
And so we get 2×5=10
So we find root of 100 that is 10
Answer:
1) The sequence is arithmetic as the same value is added each time (there is a common difference between terms).
2) First term of the sequence = -9
3) sequence generator = + 4
Step-by-step explanation:
1) The sequence is arithmetic as the same value is added each time (there is a common difference between terms).
2) First term of the sequence = -9
3) sequence generator = + 4
Question:
Plot two points that are 8 units from Point B and also share the same x-coordinate as Point B
See attachment for grid
Answer:
See attachment for plot
Step-by-step explanation:
See comment for complete question
From the attached image, we have:
Required
2 points that are 8 units away and on the same x coordinate
Let the two points be 
The first condition is that; C and D must be on the same x coordinate as B.
So, we have:
C = (-6,_)
D = (-6,_)
8 units from B implies that we add or subtract 8 from the y coordinate of B.
So, we have:
