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Mariulka [41]
3 years ago
12

Martina estimates that the surface area of the rectangular prism with a length of 13.2 feet ,a width of 6 feet , and a height of

8 feet is about 460 feet is her estimate reasonable? Explain your reasoning
Mathematics
1 answer:
Verizon [17]3 years ago
8 0
No, because 13.2 times 6=79.2
79.2 times 8=633.6
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(05.06)A chocolate bar measures 50 mm wide, 90 mm long, and 3 and 1 over 2 mm high. Will’s Wrapping Company is making a wrapper
grandymaker [24]
The surface area of a rectangular prism is always:

A=2(xy+xz+yz), where x, y, and z are the three dimensions of the prism.

A=2(50*90+50*3.5+90*3.5)

A=2(4500+175+315)

A=2(4990)

A=9980 mm^2
5 0
4 years ago
Which rule describes the x-coordinates in the translation below?. 4 2 h 1 M * 3 us A.x+0
Serggg [28]

Answer:

3 = 6 h M

Step-by-step explanation:

4 = 2 h ⋅ ( 1 M )⋅ 3 = 6 h M

you answered one of my questions before now i answer yours lol.

6 0
3 years ago
Solve for x using the<br> distributive property.<br> -2(-3+ x) = -4<br> X =<br> [?]
dlinn [17]

Answer:

x=5

Step-by-step explanation:

-2(-3+ x) = -4

Distribute

-2 * -3 + (-2) *x = -4

6 -2x = -4

Subtract 6 from each side

6 -2x-6 = -4-6

-2x = -10

Divide each side by -2

-2x/-2 = -10/-2

x = 5

3 0
3 years ago
Read 2 more answers
Jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?
mash [69]

jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?​

we know that

1 kg = 2.20462262185 lb

1 kg=2.2 lb

we have

4.2 kg

Convert to pounds

so

4.2 kg=4.2*(2.2)=9.24 pounds

therefore

the answer is 9.24 pounds

7 0
1 year ago
A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.
madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X  ≥  65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean (\mu_x) = 64  and a standard deviation (\sigma_x) = \frac{19}{\sqrt{14} }

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x} but μ=64 and σ=19 and n=14,  \mu_x=\mu=64 and \sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }

Therefore: z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X  ≥  65.6)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x}

Therefore: z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32

From z table,  P(X  ≥  65.6) =  P(z  ≥  0.32) = 1 -  P(z  <  0.32) = 1 - 0.6255 = 0.3745

P(X  ≥  65.6) = 0.3745

P(X < 68.2) = 0.7967

5 0
3 years ago
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