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Julli [10]
3 years ago
7

A certain dodgeball court is a circle with a square perfectly inscribed inside it. the square represents the playing field, whil

e the rest of the circle represents four rest areas for players. if the square has an area of 16, what is the area of the four rest areas combined?
Mathematics
1 answer:
cluponka [151]3 years ago
6 0
<span>Exactly 8*pi - 16
 Approximately 9.132741229 For this problem, we need to subtract the area of the square from the area of the circle. In order to get the area of the circle, we need to calculate its radius, which will be half of its diameter. And the diameter will be the length of the diagonal for the square. And since the area of the square is 16, that means that each side has a length of 4. And the Pythagorean theorem will allow us to easily calculate the diagonal. So: sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 4*sqrt(2) Therefore the radius of the circle is 2*sqrt(2). And the area of the circle is pi*r^2 = pi*(2*sqrt(2)) = pi*8 So the area of the rest areas is exactly 8*pi - 16, or approximately 9.132741229</span>
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A real estate agent has 1212 properties that she shows. She feels that there is a 50P% chance of selling any one property during
forsale [732]

Answer:

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The probability of a property being sold is independent of any other property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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This means that n = 12

She feels that there is a 50% chance of selling any one property during a week.

This means that p = 0.5

Compute the probability of selling no more than 6 properties in one week.

This is:

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

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P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934

P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.2256

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 + 0.1934 + 0.2256 = 0.6127

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

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