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NikAS [45]
3 years ago
12

3a^2-4|a|+6 when a = -3

Mathematics
1 answer:
kiruha [24]3 years ago
6 0
Your answer is: -33

Here is my work:

<span>3a^2-4|a|+6
</span><span>
Input -3:
=3*(-3^2)-4|-3|+6
</span>
Remove parentheses:
=3*3^2-4|-3|+6

Apply exponent rule:
=3*3^2=3^3

Apply absolute rule:
=4*3

Multiply the numbers:
=4*3=12

Bring them together:
=-3^3-12+6

Refine:
=-33
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The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

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Step-by-step explanation:

Given that :

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P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

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P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

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Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

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P(Y > 20) \simeq 0.0903

7 0
3 years ago
Can anyone help me with this question?
victus00 [196]
It is a

That the answer
3 0
3 years ago
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