Answer:
We need to select at least 1068 sales transactions.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
95% confidence level
So , z is the value of Z that has a pvalue of , so .
How many randomly selected sales transactions must be surveyed to determine the percentage that transpired over the Internet?
We need to survey at least n sales transactions.
Within three percentage points, so M = 0.03.
We do not know the population proportion, so we estimate it at , which is when we are going to need the largest sample size.
Rounding up
1068
We need to select at least 1068 sales transactions.
To solve this problem, we just need to set up a simple equation. We have that angles 1 and 2 add up to equal a right angle, or 90°, and that m<2 is 35°, so we just have to do a bit of subtraction.
<1 + <2 = 90 Given
<1 + 35 = 90 Substitute 35 for <2
<1 = 55° Subtract 35 from both sides to get rid of it, since subtraction is the opposite of addition.
Therefore, m<1 = 55°.
Hope this helps!
Y - 18 = (30 - 18)/(5 - 3) (x - 3)
y - 18 = 12/2 (x - 3)
y - 18 = 6(x - 3) = 6x - 18
y = 6x
The constant of variation (k) is 6.