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kondor19780726 [428]
3 years ago
13

Multiply and simplify to lowest terms when appropriate 11/9× 27/55

Mathematics
1 answer:
arsen [322]3 years ago
5 0
11/9 * 27/55
First, you need to transform this expression to one fraction, by multiplying the numerators between each other and put the answer as one numerator, then the denominators and put the answer as one denominator.
11/9 * 27/55 = 297/495.
Now comes the simplifying. You need to divide both numerator and denominator by the same number, till you get an irreducible fraction (a fraction In which numerator and denominator can't be divided by the same number to get another whole number).
In this case, both 297 and 495 are divisible by 99.
297/99 = 3 and 495/99 = 5.
So 297/495 = 3/5.
3 and 5 can't be divided by a same number, so 3/5 represents the irreducible and simplified fraction.

You can re-check your answer (very important):
11/9 * 27/55 = 0.6
297/495 = 0.6
3/5 = 0.6
11/9*22/55 = 297/495 = 3/5
The answer has been approved.

Hope this Helps! :) 
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A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.
vichka [17]

Answer:

14878.04878miles/hours^2

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

A=(Vf-Vi)/T where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

A=(65miles/hour - 6miles/hour)/14.8seconds, but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)

X=0.0041hours

Using X=0.0041hours in the previous equation instead of 14.8seconds we  have:

A=(65miles/hour - 6miles/hour)/0.0041hours

A=(61miles/hour)/0.0041hours

A=(61miles)/(hour*0.0041hours)

A=61miles/0.0041hours^2

A=14878.04878miles/hours^2

In conclusion, the acceleration rate is 14878.04878miles/hours^2

7 0
3 years ago
Given: AABC, m_ACB=90°,<br> CD 1 AB, m ZACD=60º,<br> BC = 6 cm<br> Find: CD, Area of AABC
just olya [345]

Answer:

Look below

Step-by-step explanation:

Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.

This means triangle BCD is a 30-60-90 (angle measures) right triangle

The proportions of the sides (from smallest to largest) is

x:x√3:2x

We are given that BC = 6 cm. This means...

2x=6

x=3

This means DB is 3 cm and CD is 3√3 cm

Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.

x=3√3

x√3=9

2x=6√3

Now we need to find AB

AB = AD + DB

AB = 9 + 3

AB = 12 cm

Area = \frac{1}{2} bh = \frac{1}{2}(12)(3\sqrt3)=6(3\sqrt3)=18\sqrt3

8 0
3 years ago
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kifflom [539]
12 + x^2..............
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Write the quadratic equation whose roots are 1 and −5, and whose leading coefficient is 4.
jarptica [38.1K]

Answer:

Standard Form: y = 4(x-1)(x+5)

Step-by-step explanation:

4 is the leading coefficient, so it should go in front. When making a standard quadratic equation, you must do the opposite for each of the roots (negative to positive, positive to negative.)

if you’re asking for a general form quadratic equation, then sorry, I am unable to help you with that :(

5 0
2 years ago
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