George shouldn't think too far.
He should use the formula for Compound Interest.
Amount in compound interest, A = P(1+ r/100)ⁿ.
Where A = Amount, P = Principal, r is the rate per year, n = number of years.
Note: the expression (1+ r/100) is raised to power n.
From George's problem: P = 750, r = 22, I guess number of years , n = x
A(x) = 750( 1 + 22/100)ˣ
A(x) = 750( 1 + 0.22)ˣ
From your options I can't see an answer. Except the expression of option (A) is actually raised to power x, and not times x as stated in the option.
tan(40) = (y + 1.5) / (x + 20)
y + 1.5 = (x + 20)[tan(40)]
y = (x + 20)[tan(40)] - 1.5
tan(60) = (y + 1.5) / x
y + 1.5 = (x)[tan(60)]
y = (x)[tan(60)] - 1.5
(x)[tan(60)] - 1.5 = (x + 20)[tan(40)] - 1.5
(x)[tan(60)] = (x + 20)[tan(40)]
(x)[tan(60)] = (x)[tan(40)] + (20)[tan(40)]
(x)[tan(60)] - (x)[tan(40)] = (20)[tan(40)]
(x)[tan(60) - tan(40)] = (20)[tan(40)]
x = [(20)(tan(40))] / [tan(60) - tan(40)]
x = 18.8 meters
Answer:
16pi mi
Step-by-step explanation:
The smallest circumference for a given area is that of a circle with that area. The area is given by ...
A = πr²
so we can find r as ...
64π = πr²
r = √64 = 8 . . . . miles
The circumference of this circle is ...
C = 2πr = 2π·(8 mi) = 16π mi
The circumference of the area is at least 16π miles.
_____
If the shape is not constrained to a circle, the circumference can be anything you like.
Answer:
I believe it's C... Not sure though...
The formula is
A=p (1+r/k)^kt
A fund needed 30000
p Amount invested?
R interest rate 0.1
K compounded semiannual 2
T time 1 year
Solve the formula for p to get
P=A÷(1+r/k)^kt
P=30,000÷(1+0.1÷2)^(2×1)
P=27,210.88
