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Hitman42 [59]
3 years ago
9

F(x)=6x^2+18 how do you solve this quadratic function?

Mathematics
1 answer:
MissTica3 years ago
8 0
F(x)=6x^2+18

Factor out the 6

F(x)=6(x^2+3)

Solve

x^2=-3

no solution
Graph never crossed x-axis
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E is the midpoint of BC. If BE = 50 and CE = 2x + 25, find the value of x.
andrew-mc [135]

Answer:

The value of x is \frac{25}{2}.

Step-by-step explanation:

From Analytical Geometry we get that ratio of BC to BE is:

\frac{BC}{BE} = 2 (From definition of midpoint)

\frac{BE+CE}{BE} = 2

1 + \frac{CE}{BE} = 2

\frac{CE}{BE} = 1

CE = BE

If we know that BE = 50 and CE = 2\cdot x + 25, then, the equality above is expanded:

2\cdot x +25 = 50

2\cdot x = 25

x = \frac{25}{2}

The value of x is \frac{25}{2}.

5 0
3 years ago
Graph the function y = 4 . Then use the graph to find the missing x- or y-coordinates for the function to the nearest hundredth.
ehidna [41]
To graph y = 4, we make a horizontal line at 4 on the y axis. See image 1


Since it is a horizontal line on the y axis, no matter the input you have for x, the y value is going to be 4. So the points <span> (4, ) (5, )  = </span><span> (4, 4) (5,4 ) 

For your point ( , 2.59), this is saying y = 2.59 The missing value would be 0. our points are below assuming the information given is complete:
</span>(4, ) (5, ) ( ,2.59)  =  (4, 4) (5,4 ) (0,2.59)

3 0
3 years ago
Read 2 more answers
A two-digit random number is chosen. What is the probability that the sum of its digits is 5?
MrMuchimi
10≤n<100

So the number of two digit numbers is 99-10+1=90

The only combinations that sum to 5 are 14, 23, 32, 41, 50 so

P(sum=5)=5/90

P(sum=5)=1/18
8 0
3 years ago
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Pls help I need this now
miv72 [106K]
The answer is A to your question
4 0
2 years ago
Need help I don’t know the answer to this.
Bond [772]

Answer:

what grade is this

Step-by-step explanation:

I'm very confused is this algebra?

8 0
2 years ago
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