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barxatty [35]
3 years ago
10

⚠️ANSWER NEEDED FAST⚠️

Mathematics
2 answers:
Sphinxa [80]3 years ago
7 0

Answer:

y = 15x

Step-by-step explanation:

If take the values of x and y you can see the equation

y=15x

VLD [36.1K]3 years ago
5 0

Answer:

2

Step-by-step explanation:

There going up times 2

15

30

45

60

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Which system is equivalent to<br> y=9x2.<br> [x+y=5
Lana71 [14]

Answer:

5-x=9x^2  

y=5-x

Step-by-step explanation:

8 0
3 years ago
A bacteria population starts with 400 bacteria and grows at a rate of r(t) = (450.263)e1.12567t bacteria per hour. How many bact
dangina [55]

Answer:

11,713 bacteria

Step-by-step explanation:

Integrating the growth rate function gives us the population of bacteria at any given moment 't', in hours:

r(t) = (450.263)e^{1.12567t} \\\int\ {r(t)} \, dt =P(t) = \frac{450.263}{1.12567}*e^{1.12567t} +C

Since at t=0, P(t) = 400, the value of C is:

P(0) = \frac{450.263}{1.12567}*e^{1.12567*0} +C\\400 = 400*1+C\\C=0

The number of bacteria after 3 hours is:

P(3) = 400*e^{1.12567*3}\\P(3) =11,713

3 0
3 years ago
Will someone please help me?
Helen [10]

Answer:

Viruses are 2 times of the bacteria.

Step-by-step explanation:

Given:

Number of viruses = 2\times 10^9

Number of bacteria = 1\times 10^9

We have to found how many times viruses are greater than the bacteria.

To find how many times,we can divide both the numbers to compare its values.

Lets

Numerator = Number of viruses

Denominator = Number of bacteria

Dividing both we have,

⇒ \frac{2\times 10^9}{1\times 10^9}

⇒ 2\times 10^(^9^-^9) ...\frac{ab^x}{cb^y}=\frac{ab^x^-^y}{c}

⇒ 2\times 10^0       ...a^0=1

⇒ 2

So the viruses are 2 times of the bacteria.

7 0
3 years ago
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Valuate 2y when y =<br>​
PtichkaEL [24]

Step-by-step explanation:

Please what is the value of y

6 0
2 years ago
The answer to 68 + (-43) is?
Zinaida [17]

Answer:

The answer is 25

4 0
3 years ago
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