It should be B

Because the slope of AB is 6/5 and when you are finding it’s perpendicular bisector then the slope of that line should be the negative reciprocal, it should be -5/6.

7 0

2 years ago

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Given that cos 63°≈ 0.454, enter the sine of a complementary angle.<br> sin

jek_recluse [69]

Answer:

$\cos(63^\circ)$ is the same as $\sin(27^\circ)$ by co-function identities

Step-by-step explanation:

Remember that complementary angles add up to 90°. The angle that i s complementary to 63° is 27°.

Also recall the co-function identities:

sin (90° – x) = cos x
cos (90° – x) = sin x

This means that $\cos(90^\circ-27^\circ)=\sin(27^\circ)\approx0.454$ .

4 0

1 year ago

Find the slope of the line that passes through the given points

7nadin3 [17]

The slope should be m= -9/11

4 0

2 years ago