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2 years ago

Pls help me! when i write A>9 it says im wrong. pls help meeeeeeeeeeeee

Mathematics

1 answer:

vovikov84 [41]2 years ago

3 0

Answer

a <_ 9 bro i dont know how to put does together (< _ )

Step-by-step explanation:

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What is the volume of the sphere that has a diameter of 3? use 3.14 for pie

aev [14]

Hey ! there

Answer:

113.04 unit cube

Step-by-step explanation:

In this question we are provided with a sphere having radius 3 units and value of π is 3.14 . And we're asked to find the volume of sphere .

For finding volume of sphere , we need to know its formula . So ,

$\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} = \dfrac{4}{3} \pi r {}^{3} }}}$

Where ,

π refers to 3.14

r refers to radius of sphere

Solution : -

Now , we are substituting value of π and radius in the formula ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times (3) {}^{3}$

Simplifying it ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times 3 \times 3 \times 3$

Cancelling 3 with 3 :

$\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}} \times 3.14 \times 3 \times 3 \times \cancel{3}$

We get ,

$\quad \longrightarrow \qquad \:4 \times 3.14 \times 9$

Multiplying 4 and 3.14 :

$\quad \longrightarrow \qquad \:12.56 \times 9$

Multiplying 12.56 and 9 :

$\quad \longrightarrow \qquad \: \pink{\underline{\boxed{\frak{113.04 \: unit \: cube}}}} \quad \bigstar$

Henceforth , volume of sphere having radius 3 units is 113 .04 units cube .

<h2>#Keep Learning</h2>

5 0

1 year ago

Dose anyone know how to solve this?

sesenic [268]

Answer:

AC is double the length of AB

so AC = 12

Step-by-step explanation:

mark me as brainliest ❤️

8 0

2 years ago

K ( t ) = t + 1 ; Find k ( 6 )

timurjin [86]

Answer:

6+1 =7

Step-by-step explanation:

therefore 7 is answer

4 0

2 years ago

Please Help!

victus00 [196]

The GCF is 2
Pull out 2 from each number:
2(2n + 5)
Hope this helps!

7 0

3 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

6 0

2 years ago