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3 years ago

Please help me, I don't understand this XD

Mathematics

2 answers:

labwork [276]3 years ago

6 0

The correct sentence is letter "B"

frez [133]3 years ago

4 0

<span>D.)A function pairs input and output values with no particular pattern.</span>

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Please Answer!

SCORPION-xisa [38]

4a-3

because 4(a-3) what’s in () can’t be done so you go to the next step in pemdas and multiply and then you write it out and your done

7 0

2 years ago

Read 2 more answers

Using the graph, what does f(8) equal?<br> PLEASE I NEED SO MUCH HELP!!

Shtirlitz [24]

Answer:

Step-by-step explanation:

The question is not terrifically worded. What it means is "What is the y value when x = 8" That's what f(8) conveys to you.

The answer (though zero is not marked and should be) is 1 unit above 0.

The answer is f(8) = 1 He's heading back.

5 0

2 years ago

For the cost function c equals 0.1 q squared plus 2.1 q plus 8, how fast does c change with respect to q when q equals 11? Det

Soloha48 [4]

Answer:

Rate of change of c with respect to q is 4.3

Percentage rate of change c with respect to q is 9.95%

Step-by-step explanation:

Cost function is given as, $c=0.1\:q^{2}+2.1\:q+8$

Given that c changes with respect to q that is, $\dfrac{dc}{dq}$ . So differentiating given function,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left (0.1\:q^{2}+2.1\:q+8 \right)$

Applying sum rule of derivative,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left(0.1\:q^{2}\right)+\dfrac{d}{dq}\left(2.1\:q\right)+\dfrac{d}{dq}\left(8\right)$

Applying power rule and constant rule of derivative,

$\dfrac{dc}{dt}=0.1\left(2\:q^{2-1}\right)+2.1\left(1\right)+0$

$\dfrac{dc}{dt}=0.1\left(2\:q\right)+2.1$

$\dfrac{dc}{dt}=0.2\left(q\right)+2.1$

Substituting the value of $q=11$ ,

$\dfrac{dc}{dt}=0.2\left(11\right)+21.$

$\dfrac{dc}{dt}=2.2+2.1$

$\dfrac{dc}{dt}=4.3$

Rate of change of c with respect to q is 4.3

Formula for percentage rate of change is given as,

$Percentage\:rate\:of\:change=\dfrac{Q'\left(x\right)}{Q\left(x\right)}\times 100$

Rewriting in terms of cost C,

$Percentage\:rate\:of\:change=\dfrac{C'\left(q\right)}{C\left(q\right)}\times 100$

Calculating value of $C\left(q \right)$

$C\left(q\right)=0.1\:q^{2}+2.1\:q+8$

Substituting the value of $q=11$ ,

$C\left(q\right)=0.1\left(11\right)^{2}+2.1\left(11\right)+8$

$C\left(q\right)=0.1\left(121\right)+23.1+8$

$C\left(q\right)=12.1+23.1+8$

$C\left(q\right)=43.2$

Now using the formula for percentage,

$Percentage\:rate\:of\:change=\dfrac{4.3}{43.2}\times 100$

$Percentage\:rate\:of\:change=0.0995\times 100$

$Percentage\:rate\:of\:change=9.95%$

Percentage rate of change of c with respect to q is 9.95%

7 0

3 years ago

Find the value of xx, yy, and zz in the rhombus below

Kamila [148]

Answer:

(0,6), (0,4), (0,-10)

Step-by-step explanation:

6 0

1 year ago

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Use Euler's Formula to find the number of vertices in the given polyhedron. 6 faces: 1 pentagon and 5 triangles

ASHA 777 [7]

Answer: There are 6 vertices in the polyhedron

Step-by-step explanation:

V- E+ F= 2

V- 10+ 6= 2

V- 4 = 2

V=6

5 0

2 years ago