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liraira [26]
3 years ago
8

Akira's dog will be having four puppies. Akira performs a

Mathematics
2 answers:
kompoz [17]3 years ago
8 0

Answer:

30% or 3/10

Step-by-step explanation:

ap%x

ivanzaharov [21]3 years ago
5 0

Answer:

50/50 but i don know how a coin toss could determine birth

Hope i helped

Step-by-step explanation:

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What is n less than 7?
Georgia [21]

n less than 7, is represented as this:

n>7

Step-by-step explanation:

You just need to think about what the question is, if it's less than, you use the > symbol to prove one variable is smaller than the other.

i hope this helps!

8 0
3 years ago
Read 2 more answers
Insert <,>,or = to make the following sentence true. square root of 17 and 4
JulijaS [17]

we can insert > to make the following sentence true that is \sqrt{17} > 4

we have to solve the following sentence

\sqrt{17} --- 4     ( insert <,>, = to make the following sentence true)

what is square root ?

The square root of a number is the factor that we can multiply by itself to get that number. The symbol for square root is  \sqrt{} .

we know that

square root of 17 is 4.12310563

which is 4+ 0.12310563

that is if we add 4+0.12310563 we get 4.12310563

therefore square root of 17 is greater than 4

that is \sqrt{17} > 4  

since 4.12310563 > 4

hence,   we can insert > to make the following sentence true that is \sqrt{17} > 4

learn more about of square root here

brainly.com/question/1387049

#SPJ4

6 0
1 year ago
Each side of a square office is 8 yards long. It will cost $65.00 per square yard to replace the carpet in the office. What woul
Sati [7]

Answer:

520 because 65 x 8 is 520

Step-by-step explanation:

7 0
3 years ago
Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5

Then the length of the arc is

\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi

4 0
3 years ago
WILL MARK BRAINLIEST
Mariulka [41]
Answer is B .....hope this help
8 0
3 years ago
Read 2 more answers
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