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torisob [31]
3 years ago
9

When constructing parallel lines , how can you verify the lines constructed are parallel

Mathematics
2 answers:
tamaranim1 [39]3 years ago
8 0

Answer:

  compare the distance between the lines at one point to the distance between the lines at another point

Step-by-step explanation:

You can construct perpendiculars at different points and compare the distance between the lines at those perpendiculars. The distance between parallel lines is the same everywhere.

koban [17]3 years ago
5 0

Answer:

just know the answer is not a

Step-by-step explanation:

i took the test and got it wrong

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Please help me thanks
drek231 [11]
6in×2=12inches and 2/5×2=0.8 so the answer would be 12.8
6 0
3 years ago
Is for over two and 20/6 proportions
ad-work [718]
No they're not proportional, and it's four*.
4/2 = 2
20/6 = 3.333333333334 or 3 1/3
4 0
4 years ago
Read 2 more answers
-6 (6-a) =-84 what is a​
Yuri [45]

Answer: A is -8

Step-by-step explanation:

-6 times 6 = -36 then you would do -6 times -a = 6a then you would have

-36 + 6a = -84 then you would add 36 to both sides to get -48 then you would divided -48 by 6 to get -8

4 0
3 years ago
Please help me with this
julsineya [31]
X is 19 and y is 84.
3 0
3 years ago
Read 2 more answers
Suppose that the waiting time for a license plate renewal at a local office of a state motor vehicle department has been found t
Wittaler [7]

Answer:

a=30 +1.04*8=38.32

So the value of height that separates the bottom 85% of data from the top 15% is 38.32.  

C) 38.32

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the waiting time in minutes of a population, and for this case we know the distribution for X is given by:

X \sim N(30,8)  

Where \mu=30 and \sigma=8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.15   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.04

And if we solve for a we got

a=30 +1.04*8=38.32

So the value of height that separates the bottom 85% of data from the top 15% is 38.32.  

C) 38.32

7 0
4 years ago
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