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MAVERICK [17]
2 years ago
12

How many different nine player batting orders can be chosen from a baseball team of 16?

Mathematics
1 answer:
lawyer [7]2 years ago
4 0
This problem is basically _{16}P_9

_nP_r = \frac{n!}{(n - r)!}

If I plug in n = 16 and r = 9

\frac{16!}{(16-9)!} = \frac{16!}{7!} = 4151347200

So there are 4151347200 different nine player batting orders that can be chosen from a baseball team of 16 :)
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