The given phrase as expression is 
Evaluate when x = 5 is 46
<em><u>Solution:</u></em>
Given that we have to write the phrase as an expression
Given phrase is:
6 more than the product of 8 and a number x
Here " more than " represents "addition" and "product" means multiplication
Therefore,
6 + product of 8 and a number x
<em><u>So the required expression is:</u></em>
<em><u>Evaluate when x = 5</u></em>
Substitute x = 5 in above expression
Thus value when x = 5 is 46
Answer: B. Unlikely
Step-by-step explanation:
Because....
You are not sure if that's possible because that's not something that happens normally so your chances are very unlikely. It's definitely not impossible because it all depends on your luck for some people it might happen. But that's why I'm saying that it's B. Unlikely.
* Hopefully this helps:) Mark me the brainliest:)!!
<em>∞∫ 234483279c20∫∞</em>
Answer:
(x-8) (x+2)
Step-by-step explanation:
x^2 – 6x – 16
Factor
What 2 numbers multiply to -16 and add to -6
-8 *2 = -18
-8+2 = -6
(x-8) (x+2)
Check the picture below.
so the perimeter of the kite is x+x+y+y, namely 2x + 2y.
![\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ x=\sqrt{8^2+15^2}\implies x=\sqrt{289}\implies \boxed{x=17} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7Bx%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B15%7D%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20x%3D%5Csqrt%7B8%5E2%2B15%5E2%7D%5Cimplies%20x%3D%5Csqrt%7B289%7D%5Cimplies%20%5Cboxed%7Bx%3D17%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \begin{cases} c=\stackrel{hypotenuse}{y}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{4}\\ \end{cases}\implies y=\sqrt{8^2+4^2}\implies y=\sqrt{80}\implies \boxed{y\approx 8.94} \\\\[-0.35em] ~\dotfill\\\\ 2x+2y\implies 2(17)+2(8.94)\implies 51.88\implies \stackrel{\textit{rounded up more}}{51.9}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7By%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B4%7D%5C%5C%20%5Cend%7Bcases%7D%5Cimplies%20y%3D%5Csqrt%7B8%5E2%2B4%5E2%7D%5Cimplies%20y%3D%5Csqrt%7B80%7D%5Cimplies%20%5Cboxed%7By%5Capprox%208.94%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%202x%2B2y%5Cimplies%202%2817%29%2B2%288.94%29%5Cimplies%2051.88%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%20more%7D%7D%7B51.9%7D)
