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3 years ago

Write the fraction in the simplest form 28/32

Mathematics

1 answer:

ch4aika [34]3 years ago

3 0

The answer is:

7/8

have a nice day :)

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Find -3A+6B A=[-3 5 -6] [9 -5 3] B=[-2 6 7] [2 -1 -6]

-Dominant- [34]

$A=\left[\begin{array}{ccc}-3&5&-6\\9&-5&3\end{array}\right];\ B=\left[\begin{array}{ccc}-2&6&7\\2&-1&-6\end{array}\right]\\\\-3A=\left[\begin{array}{ccc}(-3)(3)&(5)(3)&(-6)(3)\\(9)(3)&(-5)(3)&(3)(3)\end{array}\right]=\left[\begin{array}{ccc}-9&15&-18\\27&-15&9\end{array}\right] \\\\6B=\left[\begin{array}{ccc}(-2)(6)&(6)(6)&(7)(6)\\(2)(6)&(-1)(6)&(-6)(6)\end{array}\right]=\left[\begin{array}{ccc}-12&36&42\\12&-6&-36\end{array}\right]$

$-3A+6B=\left[\begin{array}{ccc}-9+(-12)&15+36&-18+42\\27+12&-15+(-6)&9+(-36)\end{array}\right]\\\\-3A+6B=\left[\begin{array}{ccc}-21&51&24\\39&-21&-27\end{array}\right]$

4 0

3 years ago

Five devied by three forths

bija089 [108]

Answer:

$6\dfrac{2}{3}$

Step-by-step explanation:

$\dfrac{5}{\dfrac{3}{4}} = \dfrac{5}{1}\times\dfrac{4}{3}=\dfrac{20}{3}=6\dfrac{2}{3}$

When dividing fractions, you just need to remember that all you need to do is get the inverse of the divisor and multipy.

So for the problem

5 = divident

3/4 = divisor

So we get the inverse of 3/4 which is 4/3 and then multiply.

Look above to see the process.

3 0

3 years ago

geometry question(s) on triangle similarity, please help, i’d really appreciate it! image is included.

Sergio [31]

1. D. The triangles have two given sides with an included angle, so the postulate would be SAS.

2. A. The triangles have three given sides, so the postulate would be SSS.

5 0

4 years ago

Plss helpppppp LOL LOL LOL

zzz [600]

The answer is letter c because it doesnt have a closed circle so it doesnt need a line under the >

6 0

3 years ago

11. You expect to have the given amount in an account with the given terms. Find how much you can withdraw periodically in order

Orlov [11]

This is a question on Present Value of Annuity and we seek the periodic withdrawal.

$\begin{gathered} F\text{VA}=\text{PMT(}\frac{(1+\frac{i}{m})^{nm}-1}{\frac{i}{m}}) \\ \text{Therefore, PMT=}\frac{FVA}{(\frac{(1+\frac{i}{m})^{nm}-1}{\frac{i}{m}})} \end{gathered}$

where:

FVA = Future value of annuity

PMT = Periodic Withdrawal

i = interest/discount rate

n = no of years

m = no of compundings per interest period

$\text{PMT=}\frac{300000}{(\frac{(1+\frac{0.0445}{365})^{22\times365}-1}{\frac{0.0445}{365}})}=22.01$

PMT = $22.01

8 0

1 year ago