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telo118 [61]
3 years ago
10

Write a real world scenario that matches the following equation. 15+3h=30 Then solve for the equation

Mathematics
1 answer:
arsen [322]3 years ago
7 0
Bowling costs 15 dollars per person and 3 is amount of money per game it cost to play. If you play 5 games then you pay a total of 30 dollars. 
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Do #6 for me pls and thank you!​
emmainna [20.7K]

Answer: function a

Hope this helped!

4 0
3 years ago
I thought it was if question but it is just 9
mafiozo [28]

Answer:

17-d=5

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
Read 2 more answers
Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Nastasia [14]

Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

v = x^3

For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

9 < x < 10 implies that:

(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Recall that:

v = x^3

Make x the subject

x = v^\frac{1}{3}

So, the cumulative density is:

F(x) = P(x < v^\frac{1}{3})

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right. becomes

f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

F(x) = \int\limits^{v^\frac{1}{3}}_9 1\  dx

Integrate

F(x) = [v]\limits^{v^\frac{1}{3}}_9

Expand

F(x) = v^\frac{1}{3} - 9

The density function of the volume F(v) is:

F(v) = F'(x)

Differentiate F(x) to give:

F(x) = v^\frac{1}{3} - 9

F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

8 0
2 years ago
Solve the equation<br> 12 + 4m = 24<br> A)m=9<br> B)m=8<br> C)m=3<br> D)m=-6
pantera1 [17]
12 +4m = 24

4m = 12

m = 12/4

m = 3  so choice C. is right sure 
8 0
3 years ago
What is the area of the figure?
mash [69]

Answer:

<h2>64.26 cm².</h2>

Explanation is given in the above photo.

5 0
3 years ago
Read 2 more answers
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