Ask question

Ask question

All categories

Varvara68 [4.7K]

2 years ago

15

A rectangular prism has a volume of 384 cubic centimeters. The width is twice the height, and the length is three times the heig

ht. What are the dimensions of the prism?
If you know this answer immediately because its urgent and I will also follow You!
Thank You!

1 answer:

worty [1.4K]2 years ago

7 0

Height: 4
Width: 4 * 2 = 8
Length: 4 * 3 - 12

Hope this helps you!

You might be interested in

Solve the following equation:<br> 1-31 x 8 = x<br> X =

Yuki888 [10]

Answer:

The square root of a negative number is not a real number

=

−

9

8

8

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Using the following diagram below, please answer the following:

Colt1911 [192]

The radius of the circle is 15 cm,
The diameter of the circle is 30 cm,
The circumference of the circle is 94.248 cm,
The area of the circle is 706.86 cm^2

The radius is given in the diagram as half the circle, which is 15 cm.

The diameter is double the radius because the diameter measures the circle from edge to edge, so 15•2=30 cm.

The circumference of the circle is 2•3.14•r=C,
2•3.14=6.28, 6.28•15= 94.248 cm.

The area of the circle is 3.14•r^2, so the radius squared is 225 (15•15) and 225•3.14=706.86 cm squared :)

7 0

2 years ago

I need helpI need helpI need helpI need helpI need helpI need helpI need helpI need help

Y_Kistochka [10]

Answer:

2

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

2 years ago

A store owner paid $120 wholesale price for a suit. He needs to make a 35% profit on

Juliette [100K]

Answer:

$162 to make a 35% profit

Step-by-step explanation:

35% of 120 is 42. Add the 42 to 120.

3 0

2 years ago

Read 2 more answers