Answer:
a) 0.5 = 50% of flanges exceed 1 millimeter.
b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
This means that 
(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

0.5 = 50% of flanges exceed 1 millimeter.
(b) What thickness is exceeded by 90% of the flanges?
This is x for which:

So




A thickness of 0.96 millimeters is exceeded by 90% of the flanges
(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
Answer:
29, 19, 11, 77, 37, 23. I made prime number from given digit.
I hope you got it .
The gcf of 42 and 70 is 14