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2 years ago

Can I please get Help with this math problem please

Mathematics

2 answers:

kifflom [539]2 years ago

7 0

Answer:

AB=16

BC=15

AC=12

PQ=12

QR=12

PR=19

Step-by-step explanation:

well you know that the perimeter is the sum of all sides

so we have

$(2x)+(2x+4)+(2x+3)=(2x)+(2x)+(3x+1)\\\\2x+2x+4+2x+3=2x+2x+3x+1\\\\(2x+2x+2x)+(4+3)=(2x+2x+3x)+(1)\\\\6x+7=7x+1\\\\6x+7-1=7x\\\\6x+6=7x\\\\6=7x-6x\\\\x=6$

so the sides are:

$AB=2x+4=2(6)+4=12+4=16\\\\AB=16$

$BC=2x+3=2x+4-1=16-1=15\\\\BC=15$

$AC=2x=2(6)=12\\\\AC=12$

$PQ=2x=12\\\\PQ=12$

$QR=2x=12\\\\QR=12$

$PR=3x+1=3(6)+1=18+1=19\\\\PR=19$

So there you are.

stiks02 [169]2 years ago

4 0

16 15 12 12 12 19 is the answers

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

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