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kobusy [5.1K]
4 years ago
10

43,000 rounded to the nearest thousand

Mathematics
2 answers:
Step2247 [10]4 years ago
8 0
Since all the zeros are there its already rounded
fgiga [73]4 years ago
4 0
It's already rounded
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Samuel worked at a beach stand over the summer. He worked 6 hours a day 4 days a week. He earned $7.50 per hour how much money d
Nata [24]
Total earning in the summer = $1440
Step-by-step explanation:
Earning per hour for Samuel = $7.50
No. of hours worked in a day = 6
Earning for a day = Earning per hour for Samuel *No. of hours worked in a day
Earning for a day = $7.50 *6 = $45
___________________________________________________
No of days worked in a week by Samuel = 4
Earning for week = Earning for a day *No of days worked in a week by Samuel
Earning for week = $45*4 = $180
_____________________________________________________
No. of weeks worked in summer = 8
Total earning in the summer = Earning for week *No. of weeks worked in summer
Total earning in the summer = $180*8 = $1440 (Answer)

*NOT MY ANSWER SOMEONE ALREADY ANSWERED THIS***
3 0
3 years ago
30/50 of earth atomospere is made up nitrogen while only 21/100 is made up of oxygen what fraction of earth atmosphere is either
lara31 [8.8K]

Answer:

81/100 of the atmosphere consists of those two elements

Step-by-step explanation:

3/5+21/100  >  81/100

3 0
3 years ago
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
3 years ago
Plz answer question in screen shot
liberstina [14]

Answer:

tan theta = 2 sqrt(5) /15

Step-by-step explanation:

sin theta = opp / hypotenuse

sin theta = 2/7

We can use the Pythagorean theorem to find the length of the adjacent side

a^2 + b^2 = c^2

2^2 +adj^2 = 7^2

4 + adj^2 = 49

adj ^2 = 49-4

adj^2 = 45

Taking the square root of each side

adj = sqrt(45) = sqrt(9*5) =sqrt(9) sqrt(5) = 3 sqrt(5)

The tan theta = opp/ adj

tan theta = 2 / 3 sqrt(5)

Multiply by sqrt(5) / sqrt(5)

                = 2 sqrt(5) / 3 *5

                 = 2 sqrt(5) /15

6 0
3 years ago
Please see answerrrrr
Hitman42 [59]

Answer:

1. 8/35

2. 13/35

Explanation:

You add the numbers in the parentheses first, then you multiply

1. 1/5 + 3/5 = 4/5

4/5 * 2/7 = 8/35

———————————

2. 1/5 + 3/5 * 2/7

You would multiply 3/5 and 2/7 first

1/5 + 6/35

Then you find a common denominator

1/5 = 7/35

Then you add 7/35 and 6/35

7/35 + 6/35 = 13/35

3 0
3 years ago
Read 2 more answers
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