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Tanya [424]
3 years ago
7

The scatter plot below shows the relationship between drop height and speed of a roller

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer:

b = 32.575

Step-by-step explanation:

The y-intercept is 32.575.

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What is the approximate diameter of a sphere with a volume of 268cm3
kogti [31]

Answer:

diameter ≈15.6

Step-by-step explanation:

To solve this;

volume of a sphere = 4/3 πr³

From the question given;

volume of the sphere = 268    

lets substitute   and solve for r

volume of sphere = 4/3 πr³

268 = 4/3 × 3.14 × r³

268 =4.19 × r³

Divide both-side of the equation by 4.19

268/4.19 = r³

63.96 = r³

Take the cube root of both-side

∛63.96 = r

7.8 ≈ r

but diameter = 2r = 2×7.8 =15.6

8 0
3 years ago
HELP QUESTION NUMBER FOUR
enyata [817]

Answer:

x = -1 and y = -1.

Step-by-step explanation:

The given system of equations are :

y = 4x + 3 ....(1)

y = -x - 2 ....(2)

From equation (1) and (2) :

4x + 3 = -x - 2

Taking like terms together,

4x + x = -3 -2

5x = -5

x = -1

Put the value of x in equation (1)

y = 4(-1) + 3

= -1

The solution is also shown in the attached figure. Hence, the solution is x = -1 and y = -1.

5 0
2 years ago
Magnitude of an earthquake : M = log
Gnoma [55]

Answer

4

Step-by-step explanation:

5 0
3 years ago
1. 1.4(x−1.6)=1.6(x−1.4)<br><br>solve<br>2. 1.4(x−1.6)=1.6(1.4−x)<br><br>solve
Bezzdna [24]
1.
1.4( x - 1.6) = 1.6(x - 1.4) \\ 1.4x - 2 .24 = 1.6x - 2.24 \\ 0.2x = 0 \\ x =  0
2.
1.4( x - 1.6) = 1.6(1.4 - x) \\ 1.4x - 2 .24 = 2.24 - 1.6x \\ 3x = 4.48 \\ x =  1.4933333


5 0
3 years ago
Which of the following equations could represent the points in the table? Select all that apply.
schepotkina [342]

Answer:

Options (A) and (C)

Step-by-step explanation:

From table attached,

Let the equation of a linear equation that represents the input-output values in the table is,

y - y' = m(x - x')

Where (x', y') is a point lying on the graph.

And m = slope of the line passing through two points (x_1,y_1) and (x_2,y_2)

m = \frac{y_2-y_1}{x_2-x_1}

Slope of the line passing through (0, 11) and (1, 5) will be,

m = \frac{11-5}{0-1}

m = -6

Therefore, equation of the line passing through (0, 11) and slope = -6 will be,

y - 11 = -6(x - 0)

Equation of a line passing through (1, 5) and slope = -6 will be,

y - 5 = -6(x - 1)

Equation of a line passing through (2, -1) and slope = -6 will be,

y + 1 = -6(x - 2)

Equation of a line passing through (3, -7) and slope = -6 will be,

y + 7 = -6(x - 3)

Therefore, Options (A) and (C) are the correct options.

4 0
3 years ago
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