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Yuki888 [10]
3 years ago
12

Determine the seating capacity of an auditorium with 35 rows of seats if there are 20 seats in the first row, 23 seats in the se

cond row, 26 seats in the third row, 29 seats in the forth row, and so on.
Mathematics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

  2485

Step-by-step explanation:

The number of seats in row n is given by the explicit formula for an arithmetic sequence:

  an = a1 +d(n -1)

  an = 20 +3(n -1)

The middle row is row 18, so has ...

  a18 = 20 + 3(18 -1) = 71 . . . . seats

The total number of seats is the product of the number of rows and the number of seats in the middle row:

  capacity = (71)(35) = 2485

The seating capacity is 2485.

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melisa1 [442]

Note: Consider the side of first triangle is TQ instead of TA.

Given:

Triangles TQM and TPN which share vertex T.

TQ\cong TP,TM\cong TN

To find:

The theorem which shows that \Delta TPN\cong TQM.

Solution:

In triangle TQM and TPN,

TQ\cong TP        [Given]

\angle QTM\cong \angle PTN         [Given]

TM\cong TN        [Given]

Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.

\Delta TPN\cong TQM              [SAS]

Therefore, the correct option is C.

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This is what I think

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So your answer is 1/6
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