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3 years ago

HELPPP PLEASEEEEE!!!!!

Mathematics

2 answers:

kari74 [83]3 years ago

8 0

The answer is 51. hope this helped :)

Flauer [41]3 years ago

4 0

Answer:

like 60 or something

Step-by-step explanation:

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Find the radius of the circle. The center of the circle is (2, -3) and a point that lies on the circle is (-1, -2).

kirill [66]

Answer:

$\displaystyle r = \sqrt{10}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Geometry

Definition of a radius - the center of a circle to any point to the circumference

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Center (2, -3) → x₁ = 2, y₁ = -3

Circumference point (-1, -2) → x₂ = -1, y₂ = -2

In this case, the distance d from the center to the circumference point would be the radius r of the circle.

Step 2: Find Radius r

[Distance Formula] Define equation [Radius]: $\displaystyle r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Substitute in points [Radius]: $\displaystyle r = \sqrt{(-1-2)^2+(-2--3)^2}$
[Radius] [√Radical] (Parenthesis) Simplify: $\displaystyle r = \sqrt{(-1-2)^2+(-2+3)^2}$
[Radius] [√Radical] (Parenthesis) Subtract/Add: $\displaystyle r = \sqrt{(-3)^2+(1)^2}$
[Radius] [√Radical] Evaluate exponents: $\displaystyle r = \sqrt{9+1}$
[Radius] [√Radical] Add: $\displaystyle r = \sqrt{10}$

6 0

3 years ago

Really need help the first right answer will get brainliest :)

Yuri [45]

Answer:

Step-by-step explanation:

meow WOOF WOOF

7 0

3 years ago

What is the location of the asymptote of this exponential function? Answer with an equation.

zloy xaker [14]

Answer:

y=0

Step-by-step explanation:

The asymptote of exponential equations is where is plateaus/flattens out. it will never actually touch it. Here it flattens out on the y-axis.

5 0

3 years ago

Find modulus and principle argument of compiles numbers Z=5/2(cos300+isin300)

Paul [167]

$z = \frac{5}{2}(\cos(300) + i\sin(300)) = \frac{5}{2}(\frac{1}{2} - i\frac{\sqrt{3}}{2})\\|z| = \sqrt{(\frac{5}{4})^2 + (\frac{5\sqrt{3}}{4})^2} = \sqrt{\frac{25}{16} + \frac{75}{16}} = \sqrt{\frac{100}{16}} = \frac{10}{4} = \frac{5}{2}$

7 0

3 years ago

Please help me with this

xz_007 [3.2K]

Answer:

b= -1.6

When you do inverse operations, (-1)-0.6= -1.6

8 0

4 years ago

Read 2 more answers