You will need 252 mL of pure water to obtain 0.25 mL of the desired 25% solution.
If we add X amount of water to the solution, the total amount of solution is 375+X.
And that must be 25%.
<h3>
What is the amount of solute in the current solution?</h3>
The amount of solute in the current amount of solution is
0.6(375)=225.
That amount won't change by adding water.
So we set up the equation so that the amount of solute divided by the new total amount of solution equals 25%.
225/(375+X)=0.25
cross multiply and solve
225/0.25=(375+X)
900-375=X
X=525
The pure water will you need to add to obtain the desired solution is 525.
Then we check 225/(375+525)=0.25.
To learn more about the mixture problem visit:
brainly.com/question/24647756
#SPJ1
Let the side length of the original square be x, then
1/4 x^2 = (x - 3)^2
x^2 = 4(x^2 - 6x + 9) = 4x^2 - 24x + 36
3x^2 - 24x + 36 = 0
3(x^2 - 8x + 12) = 0
x^2 - 8x + 12 = 0
x^2 - 2x - 6x + 12 = 0
x(x - 2) - 6(x - 2) = 0
(x - 6)(x - 2) = 0
x - 6 = 0 or x - 2 = 0
x = 6 or x = 2
therefore, the side length of the original square is 6 inches.
Hope this helps!
Nope the answer is -3t-1
Work:
-1/2(6t+2)
-1/2x2(3t+1)
-(3t+1)
-3t-1
