The volume of the <span>goldfish pool is V= 0.5ft x 1.5ft x 3ft=2.25 ft^3
so 7.5gallons ----------> 1 ft^3
x=? <----------- </span>2.25 ft^3
<span>x= 2.25 x 7.5 / 1= 16.87 gallons
the answer is </span>16.87 gallons of water <span>
</span>
Answer:
perimeter-
perimeter outer rectangle = 2 (l+b)
=2×8+9
= 2×17
2×17 =34 cm sq.
perimeter of inner rectangle = 2 (l+b)
= 2×5+3
=2× 8
= 16 cm sq.
perimeter of shaded portion= 34 - 16
= 18 cm sq.
area-
<em>area</em><em> </em><em>of</em><em> </em><em> </em><em>inner</em><em> </em> rectangle =l×b
l×b = 3×5
3×5=15
15 cm sq.
area of outer rectangle =l×b
l×b= 9×8
9×8= 72
72 cm sq.
area of shaded portion = 72 -15 =57 cm sq.
hey there! In second method i have done first area of inner rectangle but you have to do first area of outer rectangle...
hope it helps you....
469 + 8346 = 8,815...is that what you needed to know?
P(heads, and even and blue) = 1/2 *3/6 *1/4=1/2*1/2*1/4=1/16
P(heads, and 5, and green) = 1/2*1/6*1/4=1/48
P((heads or tail), and odd, and red)= (1/2+1/2)*3/6*1/4=1*1/2*1/4 = 1/8
P((heads or tail), and 3, and yellow)= (1/2+1/2)*1/6*1/4=1*1/6*1/4=1/24
P(tails, and prime, and not green) = 1/2 *3/6*3/4= 1/2*1/2*3/4=3/16
(Prime numbers here are 2,3 and 5)
Start by getting one of the equations in terms of one variable, in this case lets put the first equation in terms of y
2x+y=3 ---> y=3-2x
now we plug that into the second equation
5x-2y=12 ---> 5x-2(3-2x)=12
we can then multiply and simplify
5x-2(3-2x)=12 ---> 5x-6+4x=12 ---> 9x-6=12 ---> 9x=18 ---> x=2
we can now plug x=2 into an equation to solve for y
2(2)+y=3 ---> 4+y=3 ---> y=-1
