Answer:
The result is the same.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
Given the information:
- square 12 inches wide
- 3-inch diameter cookies are cut => its radius is: 1.5 inches
Hence we can find some information:
- The area of the square is:
square inches - The area of a cookies is:
π = 3.14*
= 7.065 square inches - The total number of 3-inch cookies are: 4*4 =16
=> The total area of the cookies is: 16* 7.065 = 113.04 square inches
=> how much cookie dough is "wasted" when 3-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
If the diameter is increased to 4 inches => its radius: 2 inches, we have:
- The area of a cookies is: π =
square inches - The total number of 3-inch cookies are: 3*3 =9
=> The total area of the cookies is: 9* 12.56 = 113.04 square inches
=> how much cookie dough is "wasted" when 4-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
The result is the same.
Answer:
y = - 2x + 12
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 2, thus
y = - 2x + c ← is the partial equation
To find c substitute (5, 2) into the partial equation
2 = - 10 + c ⇒ c = 2 + 10 = 12
y = - 2x + 12 ← equation of line
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL = /2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN
Answer:
10,000
Step-by-step explanation:
1000x10=
10000
