The lengths (in centimeters) of the opposite side pairs are 59 cm , 38 cm. Option C) is the correct answer.
<u>Step-by-step explanation</u>:
<u>step 1</u> :
Given that,
Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.
<u>step 2</u> :
The opposite sides are AB and CD respectively.
The another opposite sides are BC and AD respectively.
<u>step 3</u> :
If both pairs of opposite sides are congruent, then
AB = CD
44+3x = 64-x
3x+x = 64-44
4x = 20
x = 5
<u>step 4</u> :
BC = AD
33+y = 48-2y
y+2y = 48-33
3y = 15
y = 5
<u>step 5</u> :
Subsitute x=5 and y=5 in any of the given sides,
CD = 64-x = 64-5 = 59
∴ CD = 59 cm
BC = 33+y = 33+5 = 38
∴ BC = 38 cm
The lengths of the opposite side pairs are 59 cm , 38 cm.
M=ch x 4 next 3 = mch (34)
Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
A 3 I guess or a B. idk....
