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lana [24]
4 years ago
10

In a certain school,260 students were present on monday ,270 on tuesday,280 on wednesday,and 250 on thursday.find the average nu

mber of students present on those four days
Mathematics
2 answers:
photoshop1234 [79]4 years ago
8 0
The average number is 265.
marysya [2.9K]4 years ago
3 0
The answer is 1,060..
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Use the equation below to find v, if u = 18, a=6, and t =4. V=u+at​
Anastaziya [24]

Answer:42

Step-by-step explanation:

V= 18 + 6(4)

V= 18 + 24

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3 years ago
The length of a rectangle is 5 meters less than twice the width. If the area of the rectangle is 273 meters, find the dimensions
AleksandrR [38]

The length of the rectangle = 16 meters

The width of the rectangle = 10.5 meters

<u>Step-by-step explanation</u>:

Given that,

The Area of the rectangle is 273.

<u><em>Step 1</em></u><em> :</em>

Let, the width of the rectangle be 'x'

The length of the rectangle is 2x - 5

<u><em>Step 2</em></u><em> :</em>

Area of the rectangle = length \times width

                             273 = (2x - 5) x

                             273 = 2x^2 - 5x

<u><em>Step 3</em></u><em> :</em>

The equation formed is 2x^2 - 5x -273 = 0

a= coefficient of x^2 = 2

b= coefficient of x = -5

c = constant = -273

Find the roots of the equation, to find the width.

<u><em>Step 4</em></u><em> :</em>

Find the roots using factorizing method,

ac = 2\times-273 = -546 and b= -5

Factorizing -546 as -26\times21

The product of -26\times21 = -546

The sum of -26 + 21 = -5

<u><em>Step 5</em></u><em> :</em>

The roots of the equation 2x^2 - 5x -273 = 0 are x= -26/2 and x= 21/2

The values of x are x= -13 and x= 10.5

Since the width cannot be a negative value, neglect x= -13

<u><em>Step 6</em></u><em> :</em>

Therefore,

The width of the rectangle = 10.5 meters

The length of the rectangle = 2x-5

                                                = 2(10.5) - 5

                                                = 21 - 5

                                    length = 16 meters

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3 years ago
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36*(2/3) = 24
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