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lana [24]
3 years ago
10

In a certain school,260 students were present on monday ,270 on tuesday,280 on wednesday,and 250 on thursday.find the average nu

mber of students present on those four days
Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0
The average number is 265.
marysya [2.9K]3 years ago
3 0
The answer is 1,060..
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Step-by-step explanation:

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2 years ago
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Which of the following equations represents the perpendicular bisector of WX graphed below?
kotykmax [81]
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2},  \frac{y_1+y_2}{2} )=  (\frac{-5+5}{2},  \frac{2+(-4)}{2} )=(0, -1).

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is \displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}.

Thus, the slope n of the perpendicular line is \displaystyle{  \frac{5}{3}.

The equation of the line with slope \displaystyle{ n= \frac{5}{3} containing the point M(0, -1) is given by:

\displaystyle{ y-(-1)=\frac{5}{3}(x-0)

\displaystyle{ y+1= \frac{5}{3}x

\displaystyle{ 3y+3=5x

\displaystyle{ 5x-3y-3=0

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8 0
3 years ago
Brine is a solution of salt and water. If a tub contains 50 gallons of a 5% solution of brine, how much water must evaporate to
vova2212 [387]
<span>Let x = amt of water evaporated :.05(50) = .08(50-x) 2.5 = 4 - .08x .08x = 4 - 2.5 .08x = 1.5 x = 18.75 lb of water evaporated : ; Check; amt of salt remains the same, only the percentage is different, right? .05(50) = .08(50-18.75) .05(50) = .08(31.25) 2.5 = 2.5</span>
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3 years ago
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Brrunno [24]

Answer:

14 is the simplified answer, but the whole answer is 17 + -18/6

Step-by-step explanation:

Divide

−

18 by 6. h (−18) = 17 − 3 Subtract  3 from 17. h (−18)= 14

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