The best option here is option B) -14
The answer is B
Give me a thanks
Answer:
Hello! Your answer here is 10−5.
Step-by-step explanation:
To convert 0.00001 to a power of 10, we use scientific notation<em>. </em>Scientific notation is a way of expressing numbers that are too large or too small to be conveniently written in decimal form.
In this problem, the given decimal number is 0.00001. We must move the decimal 5 places to the right, which gives us 1.0.
Then, we multiply 1.0 by 10 raised to the negative of the number of places we have moved the decimal point - so we multiply 1.0 by 10−5, which gives us our answer:
10−5
Answer:
Step-by-step explanation:
If you want to factor this, you have to use the quadratic formula to do so.
![x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B%2F-%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
For us, it looks like this:
![x=\frac{-3+/-\sqrt{(-3)^2-4(5)(4)} }{2(5)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-%5Csqrt%7B%28-3%29%5E2-4%285%29%284%29%7D%20%7D%7B2%285%29%7D)
which simplifies to
![x=\frac{-3+/-\sqrt{-71} }{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-%5Csqrt%7B-71%7D%20%7D%7B10%7D)
Since it breaks every mathematical rule to have a negative number under an even index radical, we have to deal with that using the imaginary "i". You should know at this point that ![i^2=-1](https://tex.z-dn.net/?f=i%5E2%3D-1)
so we will do a rewrite on that equation above:
![x=\frac{-3+/-\sqrt{i^2*71} }{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-%5Csqrt%7Bi%5E2%2A71%7D%20%7D%7B10%7D)
which simplifies further to
![x=\frac{-3+/-i\sqrt{71} }{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-i%5Csqrt%7B71%7D%20%7D%7B10%7D)
This is the answer but we can separate it into its proper standard form which is
and ![x=-\frac{3}{10}-\frac{\sqrt{71} }{10}i](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B3%7D%7B10%7D-%5Cfrac%7B%5Csqrt%7B71%7D%20%7D%7B10%7Di)
Answer:
A.
and ![T'(3,-1)](https://tex.z-dn.net/?f=T%27%283%2C-1%29)
Step-by-step explanation:
Given:
Vertices of triangle RST are
and
.
Rotation is 90° about the center O(0,0). The rotation is counter-clockwise as the angle of rotation is positive.
Now, the co-ordinate rule for 90° rotation counter-clockwise is given as:
→ ![(-y,x)](https://tex.z-dn.net/?f=%28-y%2Cx%29)
and
values interchange their places with
becoming negative when interchanged.
So,
→ ![R'(-2,-2)](https://tex.z-dn.net/?f=R%27%28-2%2C-2%29)
→ ![S'(-1,1)](https://tex.z-dn.net/?f=S%27%28-1%2C1%29)
→
⇒
→ ![T'(3,-1)](https://tex.z-dn.net/?f=T%27%283%2C-1%29%20)
Therefore, the image of the vertices are
and
.