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Molodets [167]
3 years ago
15

¿Cuál de los siguientes puntos no pertenece a la función cuadrática f(x) = 1-x^2 ?

Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

<h2>A. (0,1)</h2>

Step-by-step explanation:

The question lacks the e=required option. Find the complete question below with options.

Which of the following points does not belong to the quadratic function

f(x) = 1-x²?

a.(0,1) b.(1,0) c.(-1,0)

Let f(x) = 0

The equation becomes 1-x² = 0

Solving 1-x² = 0 for x;

subtract 1 from both sides;

1-x²-1 = 0-1

-x² = -1

multiply both sides by minus sign

-(-x²) = -(-1)

x² = 1

take square root of both sides;

√x² = ±√1

x = ±1

x = 1 and x = -1

when x = 1

f(x) = y = 1-1²

y = 1-1

y = 0

when x = -1

f(x) = y = 1-(-1)²

y = 1-1

y = 0

Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)

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3 years ago
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Answer:

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Step-by-step explanation:

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7 0
2 years ago
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What is -3/4 multiplied by -1 1/5
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4 0
3 years ago
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Aloiza [94]

Answer:

x = -3   and   y = -4

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Step-by-step explanation:

-4x + 9y = -11 ------------------------------------------------------------------------(1)

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-12x + 27y = -33 -----------------------------------------------------------------------(3)

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y = -3

substitute y = -3 into equation (2)

-3x + 7(-3) = -9

-3x -21 = -9

add 21 to both-side of the equation

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divide both-side of the equation by -3

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8 0
3 years ago
1. What must be true about a circle with a circumference of 16 π?
snow_tiger [21]
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2. - C.) </span><span>diameter is 8

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4. - C.) </span><span>the radius.

5. - A.) 9.42

6. - D.) </span><span>16 inches or less.

7. - A.) </span><span>π

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9. - A.) 8

10. - B.) Perimeter

Hope this helps!</span>
7 0
2 years ago
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