All multiples of 10 end in a zero besides the number zero. So 10, 20, 30 and so on....
Let's assume
the price of each train ticket is x
we are given
total number of family members =5
so, total cost of ticket = total number of family members*the price of each ticket
so, total cost of ticket =5*x
so, total cost of ticket =5x
now, we have
each family member buys a boxed lunch for $6.50
so, total cost of lunch box = total number of family members*price of each lunch box
so, total cost of lunch box = 5*6.50
total cost of trip = total cost of ticket+total cost of lunch box
we are given
total cost of trip is $248.50
now, we can plug values
and we get

now, we can solve for x





so,
the price of each train ticket is $43.2..........Answer
Answer:
2.3 cm if that's an option. Not sure tho
Step-by-step explanation:
Pls mark as brainliest
To work out how much Luz earns, you simply have to follow 400/40=10, so
she earns $10/hour. We can therefore establish that if she works for 6
hours, she'll earn $60.
Answer:y=4/3
y is directly proportional to x^2 is written as
introducing a constant,
y=kx^2
but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

2=9k . <em>divi</em><em>ding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>9</em><em> </em><em>to</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>k</em>
<em>
</em>
<em>
</em>
<em>pu</em><em>tting</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>ge</em><em>neral</em><em> </em><em>expres</em><em>sion</em>
<em>
</em>
<em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>whe</em><em>n</em><em> </em><em>x</em><em>=</em><em>6</em>
<em>
</em>
<em>
</em>
<em>there</em><em>fore</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>when</em><em> </em><em>x</em><em>=</em><em>6</em><em> </em><em>is</em>
<em>4</em><em>/</em><em>3</em>