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alexgriva [62]
3 years ago
8

Y+2=1/3 (x+1) please can you help

Mathematics
1 answer:
miskamm [114]3 years ago
7 0

Equation:

y + 2 = 1/3(x+1)

Assuming you are solving for Y:

y + 2 = 1/3(x) + 1/3(1)

(y + 2) - 2 = (1/3x + 1/3) - 2

y = 1/3x + 1/3 - 2

<u>y = 1/3x - 5/3</u>

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Find two consecutive odd integers whose product is 323
Harrizon [31]
Use a let statement 
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
        -323  -323
x^2 + 2x -323 = 0

third
try to factor -323 so it is 19 and -17
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x = 19 
x = -17

hope this help

4 0
3 years ago
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Answer:

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6 0
3 years ago
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