Answer:
In mathematics, a sequence transformation is an operator acting on a given space of sequences (a sequence space). ... Sequence transformations are also commonly used to compute the antilimit of a divergent series numerically, and are used in conjunction with extrapolation methods.
Step-by-step explanation:
Answer:
3. x = 17
4. a. m<NMP = 48°
b. m<NMP = 60°
Step-by-step explanation:
3. Given that <BAM = right angle, and
m<BAM = 4x + 22, set 90° equal to 4x + 22 to find x.
4x + 22 = 90
Subtract 22 from both sides
4x + 22 - 22 = 90 - 22
4x = 68
Divide both sides by 4
4x/4 = 68/4
x = 17
4. a. m<NMQ = right angle (given)
m<PMQ = 42° (given)
m<PMQ + m<NMP = m<NMQ (angle addition postulate)
42 + m<NMP = 90 (substitution)
m<NMP = 90 - 42 (subtracting 42 from each side)
m<NMP = 48°
b. m<NMQ = right angle (given)
m<NMP = 2*m<PMQ
Let m<PMQ = x
m<NMP = 2*x = 2x
2x + x = 90° (Angle addition postulate)
3x = 90
x = 30 (dividing both sides by 3)
m<PMQ = x = 30°
m<NMP = 2*m<PMQ = 2*30
m<NMP = 60°
If you don’t know what a number is, you should substitute it for x and make an equation with the information you have been given. This gives:
(x + 8) x 2 = x - 11
Then, solve:
2x + 16 = x - 11
2x = x -27
x = -27
This can then be checked by using the number in the original text.
-27 + 8 = -19
-19 x 2 = -38
-38 is 11 less than -27.
Hope this helps :)
Solution :
The normal body temperature of any human body is considered to be 98.6
. But there is a constant debate about the body temperature of a long held standard to the body temperature.
It is given that :
Null hypothesis and alternate hypothesis :

And 
n is given as = 180
Test statistics = 3.64
Prove = 0.018 < α = 0.05 (let reject null hypothesis for α = 0.05 )
Therefore, their results are statistically significant and the result is unlikely due to chance alone.
Answer:
1
Step-by-step explanation:
Probability = number of fruit type/total number of fruit. Total number of fruit = 5 + 9 + 5 = 19.
The probability of drawing an apple is P(apple) = number of apples/total number of fruit = 5/19.
The probability of drawing a peach is P(peach) = number of peaches/total number of fruit = 9/19
The probability of drawing an apple is P(orange) = number of oranges/total number of fruit = 5/19
The probability of drawing either an apple, peach or orange at the first draw of fruit from the bag is
P(apple or peach or orange) = P(apple) + P(peach) + P(orange)
= 5/19 + 9/19 + 5/19
= (5 + 9 + 5)/19
= 19/19
= 1