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Norma-Jean [14]
4 years ago
12

Someone Helpppp me please!!

Mathematics
1 answer:
romanna [79]4 years ago
6 0

I think the answer is C or B . I’m pretty sure it’s C though .

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Delicious77 [7]
The answer would be (4,3)

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3 years ago
you flip a coin and then select one ball from a box that contains 6 balls number 1,2,3,4,5,6. how many oitcomes are in the sampl
ehidna [41]

There are 12 outcomes. The coin can land on either heads or tails, and then you can extract any number from 1 to 6 from the box. So, the outcomes are

  1. Heads, 1
  2. Heads, 2
  3. Heads, 3
  4. Heads, 4
  5. Heads, 5
  6. Heads, 6
  7. Tails, 1
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7 0
4 years ago
A local marketing company wants to estimate the proportion of consumers in the Oconee County area who would react favorably to a
Burka [1]

Answer:

C. n=423

Step-by-step explanation:

1) Notation and important concepts

Margin of error for a proportion is defined as "percentage points your results will differ from the real population value"

Confidence=90%=0.9

\alpha=1-0.9=0.1 represent the significance level defined as "a measure of the strength of the evidence that must be present in your sample before you will reject the null hypothesis and conclude that the effect is statistically significant".

\hat p=0.5 represent the sample proportion of consumers in the Oconee County area who would react favorably to a marketing campaig. For this case since we don't have enough info we use the value of 0.5 since is equiprobable the event analyzed.

z_{\alpha/2} represent a quantile of the normal standard distribution that accumulates {\alpha/2} on each tail of the distribution.

2) Formulas and solution for the problem

For this case the margin of error for a proportion is given by this formula

ME=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}   (1)

For this case the confidence level is 90% or 0.9 so then the significance would be

\alpha=1-0.9=0.1 and \alpha/2=0.05

With \alpha/2=0.05, we can find the value for z_{\alpha/2} using the normal standard distribution table or excel.

The calculated value is z_{\alpha/2}=1.644854

Now from equation (1) we need to solve for n in order to answer the question.

\frac{ME}{z_{\alpha/2}}=\sqrt{\frac{\hat p(1-\hat p)}{n}}  

Squaring both sides:

(\frac{ME}{z_{\alpha/2}})^2=\frac{\hat p(1-\hat p)}{n}

And solving for n we got:

n=\frac{\hat p(1-\hat p)}{(\frac{ME}{z_{\alpha/2}})^2}

Now we can replpace the values

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.644854})^2}=422.739

And rounded up to the nearest integer we got:

n=423

3 0
3 years ago
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avanturin [10]

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The amount he would make per hour is $12.60
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