3 years ago

Can some please help me with this question? Best answer gets full stars and brainliest. :)

Mathematics

1 answer:

bulgar [2K]3 years ago

6 0

The angle xyz would equal 56 because you add the two angles that you were given (34 and 22) and get 56

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IgorLugansk [536]

The formula for the area of a circle is A = (pi)r^2
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3 years ago

Twice the difference of a number and

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2(w-8) = 9. Hope it helps!

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3 years ago

This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)

beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

$\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}$

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

$\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}$

But equation of a hyperbola is given as

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

Substituting the values of a, b, h and k, we have

$\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}$

Hence the answer is

$\frac{x^2}{1}-\frac{y^2}{3}=1$

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Charra [1.4K]

D because that is the mean

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