Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,
Hello!
To solve this, first perform the opposite operation for the last operation (on the left side) on both sides. The last operation of the left side is squaring. Therefore, square root both sides.



Please note that you must include ±. This is because the square root of 64 can be either positive or negative, as a square of either a positive or negative number is positive.
Now, add 9 to both sides.

There are 2 solutions from here. One comes from adding 8, and the other subtracting 8. Therefore, the two solutions are:
y = 9 + 8 = 17
y = 9 - 8 = 1
Therefore, your two solutions are 17 and 1.
Hope this helps!
Answer:
Y = -1/2x+4
Step-by-step explanation:
The Y intercept is 4, so that's where the +4 comes in.
The slope is rise over run, so you count how many up you go from a whole number, in this case one, and that goes on top. Then you count how many it goes over, in this case two, and that goes on the bottom. The negative comes from which way the slope is going; down or up.
Answer:
Kindly check explanation
Step-by-step explanation:
Relative frequency = frequency / total frequency
Total frequency = 30
Outstanding = 14 / 30 = 0. 467 = 46.7%
Very good = 10/30 = 0.333 = 33.3%
Good = 5 / 30 = 0.167 = 16.7%
Average = 1 / 30 = 0.0333 = 3.3%
Poor = 0
_______Rating : frequency : R/ frequency
Outstanding _____ 14 _______0.467
Very good _______10 _______0.333
Good ___________ 5 _______ 0.167
Average _________ 1 _______ 0.033
Poor ____________ 0 _______ 0
1) 4√3 - 24√3 = -20√3
2) Multiply and simplify square root of 3 times the quantity of 4 + square root of 12:
(√3) x 4 + √12==> (√3) x 4 + √(4 x 3)==> 4√3 + 2√3 = 6√3
3) Simplify √3 + 4√3. ===> =5√3